An alternating voltage of V = V_{0} sin omega | vedclass

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(B) The instantaneous power in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$, where $\phi$ is the phase difference between voltage and c

Vedclass · Accepted Answer

$0$ watt

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(B) The instantaneous power in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$, where $\phi$ is the phase difference between voltage and current.Given voltage $V = V_{0} \sin \omega t$ and current $I = I_{0} \sin (\omega t - \frac{\pi}{2})$.The phase difference $\phi = \frac{\pi}{2}$.The power consumed is $P = V_{rms} I_{rms} \cos \phi = \frac{V_{0}}{\sqrt{2}} \cdot \frac{I_{0}}{\sqrt{2}} \cdot \cos(\frac{\pi}{2})$.Since $\cos(\frac{\pi}{2}) = 0$, the power consumed $P = 0$ watt.

An alternating voltage of $V = V_{0} \sin \omega t$ is applied across a circuit. As a result, a current $I = I_{0} \sin (\omega t - \frac{\pi}{2})$ flows in it. The power consumed per cycle is . . . . . . .

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