An amine (X) reacts with p-toluene sulphonyl | vedclass

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Question

(D) secondary amine reacts with Hinsberg reagent ($p-$toluene sulphonyl chloride) to form a corresponding sulphonamide that is insoluble in aqueous $N

Vedclass · Accepted Answer

$CH_3CH_2N(CH_3)COC_6H_5$

Vedclass · Answer

(D) secondary amine reacts with Hinsberg reagent ($p-$toluene sulphonyl chloride) to form a corresponding sulphonamide that is insoluble in aqueous $NaOH$. Thus,'$X$' must be a secondary amine. The reaction of a secondary amine $(R_1R_2NH)$ with benzoyl chloride $(C_6H_5COCl)$ is a benzoylation reaction (Schotten-Baumann reaction),which yields an $N,N-$disubstituted benzamide. Given the options,the secondary amine '$X$' is $N-$methylethanamine $(CH_3CH_2NHCH_3)$. The reaction is: $CH_3CH_2NHCH_3 + C_6H_5COCl \rightarrow CH_3CH_2N(CH_3)COC_6H_5 + HCl$.

An amine $(X)$ reacts with $p-$toluene sulphonyl chloride to give the product,$Y$,which is insoluble in alkali. The product of $X$ with benzoyl chloride is

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