An ammeter gives full-scale deflection when a current of $2 \, A$ flows through it. The resistance of the ammeter is $12 \, \Omega$. If the same ammeter is to be used for measuring a maximum current of $5 \, A$,then the ammeter must be connected with a resistance of:

  • A
    $8 \, \Omega$ in series
  • B
    $18 \, \Omega$ in series
  • C
    $8 \, \Omega$ in parallel
  • D
    $18 \, \Omega$ in parallel

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Similar Questions

$A$ galvanometer coil has a resistance of $15\; \Omega$ and the meter shows full-scale deflection for a current of $4\; mA$. How will you convert the meter into an ammeter of range $0$ to $6\; A$?

The resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current up to $100\, A$. After an additional shunt has been connected to this ammeter,it becomes possible to measure currents up to $750\, A$ by this meter. The value of the shunt resistance is:

$A$ galvanometer of resistance $200 \Omega$ is to be converted into an ammeter. The value of shunt resistance which allows $3 \%$ of the main current through the galvanometer is equal to (nearly) (in $\Omega$)

$A$ moving coil galvanometer has a coil with $175$ turns and an area of $1 \, cm^2$. It uses a torsion band with a torsion constant of $10^{-6} \, N \cdot m/rad$. The coil is placed in a magnetic field $B$ parallel to its plane. The coil deflects by $10^{\circ}$ for a current of $1 \, mA$. The value of $B$ (in Tesla) is approximately:

What will be the resistance of the shunt when $5 \%$ of the main current is passed through a galvanometer of resistance $G$?

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