An amplitude modulated wave is modulated to $50\%$. What is the saving in power if the carrier as well as one of the sidebands are suppressed?

The maximum and minimum amplitude of an amplitude modulated wave is $16\, V$ and $8\, V$ respectively. The modulation index for this amplitude modulated wave is $x \times 10^{-2}$. The value of $x$ is .........

$A$ message signal of $3 \text{ kHz}$ is used to modulate a carrier signal of frequency $1 \text{ MHz}$ using amplitude modulation. The upper sideband frequency and bandwidth respectively are:

An amplitude modulated signal is given by $V(t) = 10[1 + 0.6 \cos(2.2 \times 10^4 t)] \sin(5.5 \times 10^5 t)$, where $t$ is in seconds. The sideband frequencies (in $kHz$) are: [Given $\pi = 22/7$]

$A$ carrier wave of frequency $1000 \text{ kHz}$ is modulated by an audio signal of frequency $800 \text{ Hz}$. What are the frequencies of the first pair of sidebands?

$A$ message signal of frequency $50 / \pi \text{ kHz}$ and peak voltage of $5 \text{ V}$ is used to modulate a carrier of frequency $1 \text{ MHz}$ and peak voltage $20 \text{ V}$. The modulation index is