An aromatic compound A of the molecular formu | vedclass

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(B) The formation of a yellow precipitate with $I_2$ and dilute $NaOH$ is the characteristic iodoform test. This test is given by compounds containing

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$C_6H_5CH(OH)CH_3$

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(B) The formation of a yellow precipitate with $I_2$ and dilute $NaOH$ is the characteristic iodoform test. This test is given by compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ group attached to a carbon atom or a hydrogen atom.Given the molecular formula $C_8H_{10}O$,the compound $C_6H_5CH(OH)CH_3$ ($1$-phenylethanol) contains the $CH_3CH(OH)-$ group.Upon reaction with $I_2$ and $NaOH$,$C_6H_5CH(OH)CH_3$ undergoes oxidation to acetophenone,which then reacts further to form iodoform $(CHI_3)$,a yellow precipitate,and sodium benzoate.

An aromatic compound $A$ of the molecular formula $C_8H_{10}O$ on reaction with iodine and dilute $NaOH$ gives a yellow precipitate. The structure of the compound is expected to be

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