An aromatic compound A of formula C_7H_6Cl_2 | vedclass

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(A) Compound $A$ is $p-$chlorobenzyl chloride $(Cl-C_6H_4-CH_2Cl)$. It reacts with alcoholic $AgNO_3$ to form $AgCl$ due to the presence of a reactive

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$p-$chlorobenzyl chloride

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(A) Compound $A$ is $p-$chlorobenzyl chloride $(Cl-C_6H_4-CH_2Cl)$. It reacts with alcoholic $AgNO_3$ to form $AgCl$ due to the presence of a reactive benzylic chloride group. Treatment with $NaOH$ results in the nucleophilic substitution of the benzylic chlorine to form $p-$chlorobenzyl alcohol $(Cl-C_6H_4-CH_2OH)$,which corresponds to the formula $C_7H_7OCl$. Oxidation of the side chain of $A$ yields $p-$chlorobenzoic acid. Due to the symmetry of the $p-$substituted benzene ring,$p-$chlorobenzoic acid provides only one mononitro derivative upon nitration.

An aromatic compound $A$ of formula $C_7H_6Cl_2$ gives $AgCl$ on boiling with alcoholic $AgNO_3$ solution,and yields $C_7H_7OCl$ on treatment with sodium hydroxide. $A$ on oxidation gives a monochlorobenzoic acid which affords only one mononitro derivative. The compound $A$ is :

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