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(D) Given: Focal length of objective $f_o = 20 \, m = 2000 \, cm$,Focal length of eyepiece $f_e = 2 \, cm$.$1$. Magnification $(m)$: For a telescope i

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(D) Given: Focal length of objective $f_o = 20 \, m = 2000 \, cm$,Focal length of eyepiece $f_e = 2 \, cm$.$1$. Magnification $(m)$: For a telescope in normal adjustment,$m = \frac{f_o}{f_e} = \frac{2000 \, cm}{2 \, cm} = 1000$.$2$. Tube length $(L)$: For normal adjustment,$L = f_o + f_e = 20 \, m + 0.02 \, m = 20.02 \, m$.$3$. Nature of image: An astronomical telescope forms an inverted image with respect to the object.Since all statements are correct,the correct option is $D$.

An astronomical refracting telescope has an objective of focal length $20 \, m$ and an eyepiece of focal length $2 \, cm$. Then:

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