An astronomical telescope has an angular magn | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an astronomical telescope with the final image at infinity (normal adjustment),the angular magnification is given by $|m| = \frac{f_o}{f_e} =

Vedclass · Accepted Answer

$f_o = 30 \, cm$ and $f_e = 6 \, cm$

Vedclass · Answer

(D) For an astronomical telescope with the final image at infinity (normal adjustment),the angular magnification is given by $|m| = \frac{f_o}{f_e} = 5$. This implies $f_o = 5f_e$ ... $(i)$. The length of the telescope tube is the sum of the focal lengths of the objective and the eyepiece: $L = f_o + f_e = 36 \, cm$ ... $(ii)$. Substituting $(i)$ into $(ii)$,we get $5f_e + f_e = 36 \, cm$,which simplifies to $6f_e = 36 \, cm$. Thus,$f_e = 6 \, cm$. Substituting $f_e$ back into $(i)$,we get $f_o = 5 	imes 6 \, cm = 30 \, cm$. Therefore,the focal lengths are $f_o = 30 \, cm$ and $f_e = 6 \, cm$.

An astronomical telescope has an angular magnification of magnitude $5$ for distant objects. The separation between the objective and the eyepiece is $36 \, cm$ and the final image is formed at infinity. The focal length $f_o$ of the objective and the focal length $f_e$ of the eyepiece are:

Similar Questions

When the tube length of an astronomical telescope is increased,its magnifying power will .......

The magnifying power of a telescope with tube length $60 \; cm$ is $5$. What is the focal length of its eyepiece in $cm$?

In an astronomical telescope in normal adjustment,a straight black line of length $L$ is drawn on the objective lens. The eyepiece forms a real image of this line. The length of this image is $l$. The magnification of the telescope is

If the length of the tube of an astronomical telescope is $105 \, cm$ and its magnification power for normal adjustment is $20$,then the focal length of its objective lens will be ....... $cm$.

If the focal lengths of the objective and eyepiece of an astronomical telescope are $200 \, cm$ and $4 \, cm$ respectively,what will be the magnifying power for distant vision (normal adjustment)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module