An atom of an element contains $29$ electrons and $35$ neutrons. Deduce
$(i)$ the number of protons and
$(ii)$ the electronic configuration of the element.

(N/A) $(i)$ For a neutral atom,the number of protons is equal to the number of electrons.
$\therefore$ Number of protons $= 29$.
$(ii)$ The atomic number $(Z)$ is $29$,which corresponds to Copper $(Cu)$. The electronic configuration is $1s^{2} \, 2s^{2} \, 2p^{6} \, 3s^{2} \, 3p^{6} \, 3d^{10} \, 4s^{1}$.