An atom of mass number 15 and atomic number 7 | vedclass

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(D) The initial nucleus is $^7_7X^{15}$.An $\alpha$-particle is a helium nucleus,represented as $^2_2He^4$.The reaction of the atom capturing an $\alp

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$18$ and $8$

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(D) The initial nucleus is $^7_7X^{15}$.An $\alpha$-particle is a helium nucleus,represented as $^2_2He^4$.The reaction of the atom capturing an $\alpha$-particle is: $^7_7X^{15} + ^2_2He^4 	o ^{19}_9Y^*$.Then,the resulting nucleus emits a proton $(^1_1H^1)$:$^{19}_9Y^* 	o ^1_1H^1 + ^{18}_8Z$.Comparing the mass numbers: $15 + 4 = 1 + A \implies A = 18$.Comparing the atomic numbers: $7 + 2 = 1 + Z \implies Z = 8$.Thus,the resulting product has a mass number of $18$ and an atomic number of $8$.

An atom of mass number $15$ and atomic number $7$ captures an $\alpha$-particle and then emits a proton. The mass number and atomic number of the resulting product will respectively be

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