An atomic nucleus $_{90}^{232}Th$ emits several $\alpha$ and $\beta$ radiations and finally reduces to $_{82}^{208}Pb$. It must have emitted:

  • A
    $4 \alpha$ and $2 \beta$
  • B
    $8 \alpha$ and $24 \beta$
  • C
    $6 \alpha$ and $4 \beta$
  • D
    $4 \alpha$ and $16 \beta$

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In a radioactive decay chain reaction,${ }_{90}^{230} Th$ nucleus decays into ${ }_{84}^{214} Po$ nucleus. The ratio of the number of $\alpha$ to number of $\beta^{-}$ particles emitted in this process is. . . . .

Arrange the radioactive radiations in increasing order of their ionizing power and penetrating power.

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