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(B) The power output of the reactor is $P = 300\, MW = 300 	imes 10^6\, J/s$.The energy released per fission is $E = 170\, MeV = 170 	imes 10^6 	im

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$4 	imes 10^{22}$

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(B) The power output of the reactor is $P = 300\, MW = 300 	imes 10^6\, J/s$.The energy released per fission is $E = 170\, MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19}\, J = 2.72 	imes 10^{-11}\, J$.The number of fissions per second is given by $n/t = P/E$.$n/t = (300 	imes 10^6) / (2.72 	imes 10^{-11}) \approx 1.103 	imes 10^{19}$ atoms per second.To find the number of atoms fissioned per hour,we multiply by $3600\, s$:$N = (1.103 	imes 10^{19}) 	imes 3600 \approx 3.97 	imes 10^{22} \approx 4 	imes 10^{22}$ atoms.

An atomic power nuclear reactor can deliver $300\, MW$. The energy released due to fission of each nucleus of a uranium atom ${U^{238}}$ is $170\, MeV$. The number of uranium atoms fissioned per hour will be

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