An earthquake generates both transverse S and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the distance of the epicenter of the earthquake from the point of observation be $d$.Speed of $S$-wave, $v_S = 4.5 \,km/s$.Speed of $P$-wave,

Vedclass · Accepted Answer

$2160$

Vedclass · Answer

(C) Let the distance of the epicenter of the earthquake from the point of observation be $d$.Speed of $S$-wave, $v_S = 4.5 \,km/s$.Speed of $P$-wave, $v_P = 8.0 \,km/s$.Since the distance $d$ is the same for both waves, we have $d = v_P t_P = v_S t_S$.Thus, $8.0 t_P = 4.5 t_S$, which gives $t_P = \frac{4.5}{8.0} t_S \quad \dots (i)$.The first $P$-wave arrives $3.5 \,min$ earlier than the first $S$-wave, so $t_S - t_P = 3.5 \,min = 3.5 	imes 60 \,s = 210 \,s \quad \dots (ii)$.Substituting $(i)$ into $(ii)$:$t_S - \frac{4.5}{8.0} t_S = 210$$\frac{8.0 t_S - 4.5 t_S}{8.0} = 210$$\frac{3.5 t_S}{8.0} = 210$$t_S = \frac{210 	imes 8.0}{3.5} = 480 \,s$.Now, calculating the distance $d = v_S t_S = 4.5 \,km/s 	imes 480 \,s = 2160 \,km$.

Similar Questions

Why are the bells in temples and schools made of metal and not of wood?

Consider the sound wave travelling in ideal gases of $He$,$CH_4$,and $CO_2$. All the gases have the same ratio $\frac{P}{\rho}$,where $P$ is the pressure and $\rho$ is the density. The ratio of the speed of sound through the gases $V_{He}: V_{CH_4}: V_{CO_2}$ is given by

If the pressure, temperature, and density of an ideal gas are denoted by $p, T$ and $\rho$, respectively, the velocity of sound in the gas is

Sound waves travel at $350 \text{ m/s}$ through warm air and at $3500 \text{ m/s}$ through brass. Which of the following is correct about the wavelength of a $700 \text{ Hz}$ acoustic wave as it enters brass from warm air?

What is the distance between consecutive condensation and rarefaction in longitudinal waves?

Vedclass Test Series

Exam Paper Generator

Online Exam Module