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(A) The power $P$ consumed by an electric bulb is given by the formula $P = \frac{V^2}{R}$,where $V$ is the voltage and $R$ is the resistance of the f

Vedclass · Accepted Answer

$484$

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(A) The power $P$ consumed by an electric bulb is given by the formula $P = \frac{V^2}{R}$,where $V$ is the voltage and $R$ is the resistance of the filament.Rearranging the formula to solve for resistance $R$,we get $R = \frac{V^2}{P}$.Given values are $P = 100\, W$ and $V = 220\, V$.Substituting these values into the formula: $R = \frac{220 	imes 220}{100}$.$R = \frac{48400}{100} = 484\,\Omega$.Therefore,the resistance of the filament is $484\,\Omega$.

An electric bulb of $100\, W$ is connected to a supply of electricity of $220\, V$. The resistance of the filament is ............. $\Omega$.

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