An electric current i_1 can flow in either di | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic flux $\phi_2$ linked with loop $(2)$ is proportional to the current $i_1$ in loop $(1)$,given by $\phi_2 = M i_1$,where $M$ is the mu

Vedclass · Accepted Answer

Vedclass · Answer

(D) The magnetic flux $\phi_2$ linked with loop $(2)$ is proportional to the current $i_1$ in loop $(1)$,given by $\phi_2 = M i_1$,where $M$ is the mutual inductance.According to Faraday's law of electromagnetic induction,the induced emf $\varepsilon_2$ in loop $(2)$ is $\varepsilon_2 = -\frac{d\phi_2}{dt} = -M \frac{di_1}{dt}$.The induced current $i_2$ is given by $i_2 = \frac{\varepsilon_2}{R} = -\frac{M}{R} \frac{di_1}{dt}$,where $R$ is the resistance of loop $(2)$.From the given graph,$i_2$ is a positive constant value. This implies that $\frac{di_1}{dt}$ must be a negative constant.Therefore,the current $i_1$ must be decreasing linearly with time $t$ (i.e.,having a negative slope).Looking at the options,the graph where $i_1$ decreases linearly with time $t$ corresponds to option $(D)$.

Similar Questions

If a change in current of $0.01 \,A$ in one coil produces a change in magnetic flux of $2 \times 10^{-2} \,Wb$ in the other coil,then the mutual inductance of the two coils in henry is (in $\,H$)

The mutual inductance of a system of two coils does not depend on . . . . . . .

Two coils of self-inductances $2\, mH$ and $8\, mH$ are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is......$mH$.

$A$ transformer works on the principle of

$A$ coil of radius '$r$' is placed on another coil (whose radius is '$R$' and current flowing through it is changing) so that their centres coincide $(R \gg r)$. If both the coils are coplanar,then the mutual inductance between them is $(\mu_0 = \text{permeability of free space})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module