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(B) For wires connected in parallel,the potential difference $V$ across each wire is the same.The current $i$ in a wire is given by $i = V/R$,where $R

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$1/3$

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(B) For wires connected in parallel,the potential difference $V$ across each wire is the same.The current $i$ in a wire is given by $i = V/R$,where $R$ is the resistance.Resistance $R$ is given by $R = ho \frac{l}{A} = ho \frac{l}{\pi r^2}$.Since the material is the same,the resistivity $ho$ is constant.Therefore,the ratio of currents is $\frac{i_1}{i_2} = \frac{R_2}{R_1} = \frac{l_2}{l_1} 	imes \left( \frac{r_1}{r_2} ight)^2$.Given $\frac{l_1}{l_2} = \frac{4}{3}$ and $\frac{r_1}{r_2} = \frac{2}{3}$.Substituting these values: $\frac{i_1}{i_2} = \frac{3}{4} 	imes \left( \frac{2}{3} ight)^2 = \frac{3}{4} 	imes \frac{4}{9} = \frac{1}{3}$.

An electric current is passed through a circuit containing two wires of the same material,connected in parallel. If the lengths and radii of the wires are in the ratio of $4/3$ and $2/3$ respectively,then the ratio of the currents passing through the wires will be:

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