An electric dipole of length 0.5 text{ }mutex | vedclass

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(C) The torque $	au$ experienced by an electric dipole in a uniform electric field is given by the formula: $	au = pE \sin 	heta$, where $p = q \cd

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$2$

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(C) The torque $	au$ experienced by an electric dipole in a uniform electric field is given by the formula: $	au = pE \sin 	heta$, where $p = q \cdot (2a)$ is the dipole moment.Given:Length of dipole $2a = 0.5 	ext{ }\mu	ext{m} = 0.5 	imes 10^{-6} 	ext{ m}$.Electric field $E = 10^4 	ext{ V/m}$.Angle $	heta = 30^{\circ}$.Torque $	au = 5 	imes 10^{-9} 	ext{ Nm}$.Substituting the values into the formula:$5 	imes 10^{-9} = q 	imes (0.5 	imes 10^{-6}) 	imes 10^4 	imes \sin 30^{\circ}$$5 	imes 10^{-9} = q 	imes (0.5 	imes 10^{-6}) 	imes 10^4 	imes 0.5$$5 	imes 10^{-9} = q 	imes 2.5 	imes 10^{-3}$$q = \frac{5 	imes 10^{-9}}{2.5 	imes 10^{-3}}$$q = 2 	imes 10^{-6} 	ext{ C} = 2 	ext{ }\mu	ext{C}$.

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