An electric dipole with dipole moment 5 times | vedclass

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(B) Given:Dipole moment $p = 5 	imes 10^{-6} \ Cm$Electric field $E = 4 	imes 10^5 \ N/C$Initial angle $	heta_{i} = 0^{\circ}$Final angle $	heta_{

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(B) Given:Dipole moment $p = 5 	imes 10^{-6} \ Cm$Electric field $E = 4 	imes 10^5 \ N/C$Initial angle $	heta_{i} = 0^{\circ}$Final angle $	heta_{f} = 60^{\circ}$The potential energy of an electric dipole in an electric field is given by $U = -pE \cos 	heta$.The change in potential energy is $\Delta U = U_{f} - U_{i}$.$\Delta U = (-pE \cos 	heta_{f}) - (-pE \cos 	heta_{i})$$\Delta U = pE (\cos 	heta_{i} - \cos 	heta_{f})$Substituting the values:$\Delta U = (5 	imes 10^{-6}) 	imes (4 	imes 10^5) 	imes (\cos 0^{\circ} - \cos 60^{\circ})$$\Delta U = 20 	imes 10^{-1} 	imes (1 - 0.5)$$\Delta U = 2 	imes 0.5 = 1 \ J$.

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