An electric field of 1000,V/m is applied to a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The potential energy $U$ of an electric dipole in an external electric field is given by the formula:$U = -\vec{P} \cdot \vec{E} = -PE \cos 	heta

Vedclass · Accepted Answer

$-7 	imes 10^{-27}\,J$

Vedclass · Answer

(B) The potential energy $U$ of an electric dipole in an external electric field is given by the formula:$U = -\vec{P} \cdot \vec{E} = -PE \cos 	heta$Given values:Electric field $E = 1000\,V/m = 10^3\,V/m$Dipole moment $P = 10^{-29}\,C\cdot m$Angle $	heta = 45^\circ$Substituting the values into the formula:$U = -(10^{-29}) 	imes (10^3) 	imes \cos(45^\circ)$$U = -10^{-26} 	imes \frac{1}{\sqrt{2}}$$U = -10^{-26} 	imes 0.7071$$U = -0.7071 	imes 10^{-26}\,J$$U = -7.071 	imes 10^{-27}\,J$Rounding to the nearest provided option,we get:$U \approx -7 	imes 10^{-27}\,J$

An electric field of $1000\,V/m$ is applied to an electric dipole at an angle of $45^\circ$. The value of the electric dipole moment is $10^{-29}\,C\cdot m$. What is the potential energy of the electric dipole?

Similar Questions

$A$ point $Q$ lies on the perpendicular bisector of an electric dipole with dipole moment $p$. If the distance of $Q$ from the dipole is $r$ (where $r$ is much larger than the size of the dipole),then the electric field at $Q$ is proportional to:

Two electric dipoles of moment $P$ and $64 P$ are placed in opposite directions on a line at a distance of $25 \ cm$. The electric field will be zero at a point between the dipoles whose distance from the dipole of moment $P$ is.....$cm$.

The figure shows the electric field lines around an electric dipole. Which of the arrows best represents the electric field at point $P$?

The electric field due to a dipole at a distance $r$ on its axis is

$A$ dipole is placed in an electric field as shown. In which direction will it move?

Vedclass Test Series

Exam Paper Generator

Online Exam Module