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(D) The energy of a photon is given by $E = h
u = \frac{hc}{\lambda}$.Given $E = 14.4 	ext{ keV} = 14.4 	imes 10^3 	imes 1.6 	imes 10^{-19} 	ext

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$X$-ray

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(D) The energy of a photon is given by $E = h
u = \frac{hc}{\lambda}$.Given $E = 14.4 	ext{ keV} = 14.4 	imes 10^3 	imes 1.6 	imes 10^{-19} 	ext{ J} = 2.304 	imes 10^{-15} 	ext{ J}$.Using the relation $\lambda = \frac{hc}{E}$,where $hc \approx 1240 	ext{ eV} \cdot 	ext{nm} = 1.24 	imes 10^{-6} 	ext{ eV} \cdot 	ext{m}$.$\lambda = \frac{1240 	ext{ eV} \cdot 	ext{nm}}{14.4 	imes 10^3 	ext{ eV}} \approx 0.086 	ext{ nm} = 0.86 	imes 10^{-10} 	ext{ m}$.Since the wavelength range for $X$-rays is approximately $10^{-8} 	ext{ m}$ to $10^{-13} 	ext{ m}$,this radiation falls into the $X$-ray region.

An electromagnetic radiation has an energy of $14.4 \text{ keV}$. To which region of the electromagnetic spectrum does it belong?

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