An electromagnetic wave of intensity 1400 ~W/ | vedclass

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Question

(D) The radiation pressure $P$ exerted by an electromagnetic wave that is completely absorbed is given by $P = \frac{I}{c}$,where $I$ is the intensity

Vedclass · Accepted Answer

$7 	imes 10^{-6} ~N$

Vedclass · Answer

(D) The radiation pressure $P$ exerted by an electromagnetic wave that is completely absorbed is given by $P = \frac{I}{c}$,where $I$ is the intensity and $c$ is the speed of light $(c = 3 	imes 10^8 ~m/s)$.The force $F$ exerted on the surface is given by $F = P 	imes A$,where $A$ is the area of the surface.Substituting the given values: $F = \frac{I 	imes A}{c}$$F = \frac{1400 ~W/m^2 	imes 1.5 ~m^2}{3 	imes 10^8 ~m/s}$$F = \frac{2100}{3 	imes 10^8} ~N$$F = 700 	imes 10^{-8} ~N = 7 	imes 10^{-6} ~N$.

An electromagnetic wave of intensity $1400 ~W/m^2$ falls on a metal surface of area $1.5 ~m^2$ and is completely absorbed by it. Find the force exerted by the beam.

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