An electron having a charge e moves with a ve | vedclass

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(D) The magnetic force $\vec{F}$ on a moving charge $q$ in a magnetic field $\vec{B}$ is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	im

Vedclass · Accepted Answer

Negative direction of $z$-axis

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(D) The magnetic force $\vec{F}$ on a moving charge $q$ in a magnetic field $\vec{B}$ is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.For an electron,the charge $q = -e$.The velocity vector is $\vec{v} = v\hat{i}$ and the magnetic field vector is $\vec{B} = B\hat{j}$.Substituting these into the formula,we get: $\vec{F} = -e(v\hat{i} 	imes B\hat{j})$.Since $\hat{i} 	imes \hat{j} = \hat{k}$,the force is $\vec{F} = -evB\hat{k}$.This indicates that the force acts in the negative $z$-direction.Therefore,the correct option is $(d)$.

An electron having a charge $e$ moves with a velocity $\vec{v}$ in the positive $x$-direction. $A$ magnetic field $\vec{B}$ acts on it in the positive $y$-direction. The force on the electron acts in (where the outward direction is taken as the positive $z$-axis):

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