(A) The magnetic force on a moving charge is given by the Lorentz force formula: $\overrightarrow{F} = q(\overrightarrow{v} \times \overrightarrow{B})

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(A) The magnetic force on a moving charge is given by the Lorentz force formula: $\overrightarrow{F} = q(\overrightarrow{v} \times \overrightarrow{B})$.For an electron,$q = -e$. The velocity vector is $\overrightarrow{v} = v\hat{i}$ and the magnetic field is $\overrightarrow{B} = -B\hat{k}$.Substituting these values: $\overrightarrow{F} = -e(v\hat{i} \times -B\hat{k}) = evB(\hat{i} \times \hat{k}) = evB(-\hat{j})$.Thus,the force acts along the negative $y$-axis ($B$ is correct).Since the magnetic force is always perpendicular to the velocity,it acts as a centripetal force,causing the electron to move in a circular path ($E$ is correct).Therefore,the correct options are $B$ and $E$.

Class 12 Physics Moving Charges and Magnetism Motion of Charged Particle In Magnetic Field

Medium

An electron is moving along the positive $x$-axis. If a uniform magnetic field is applied parallel to the negative $z$-axis,then:
$A.$ The electron will experience a magnetic force along the positive $y$-axis.
$B.$ The electron will experience a magnetic force along the negative $y$-axis.
$C.$ The electron will not experience any force in the magnetic field.
$D.$ The electron will continue to move along the positive $x$-axis.
$E.$ The electron will move along a circular path in the magnetic field.
Choose the correct answer from the options given below:

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$B$ and $E$ only
B
$A$ and $E$ only
C
$C$ and $D$ only
D
$B$ and $D$ only

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Moving Charges and Magnetism

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Motion of Charged Particle In Magnetic Field

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