An electron is moving along the positive X-ax | vedclass

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(A) The force on a moving charge in a magnetic field is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.For the electron to

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$Y$-axis

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(A) The force on a moving charge in a magnetic field is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.For the electron to reverse its direction,it must follow a semi-circular path in a plane perpendicular to the magnetic field.If the electron is moving along the positive $X$-axis (velocity $\vec{v} = v\hat{i}$),and we apply a magnetic field along the $Y$-axis $(\vec{B} = B\hat{j})$,the force will be $\vec{F} = -e(v\hat{i} 	imes B\hat{j}) = -evB\hat{k}$.This force acts in the $Z$-direction,causing the electron to move in a semi-circle in the $X-Z$ plane.After completing a semi-circle,the velocity vector will point in the negative $X$-direction $(-v\hat{i})$,effectively reversing the electron's direction.Thus,applying the magnetic field along the $Y$-axis (or $Z$-axis) will achieve the desired result.

An electron is moving along the positive $X$-axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative $X$-axis. This can be done by applying the magnetic field along

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