(C) In free space, the de Broglie wavelength is given by $\lambda_0 = h/mv$.When the electron enters the medium, its velocity is reduced by $20\%$.The

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(C) In free space, the de Broglie wavelength is given by $\lambda_0 = h/mv$.When the electron enters the medium, its velocity is reduced by $20\%$.Therefore, the new velocity $v' = v - 0.20v = 0.8v$.The new de Broglie wavelength in the medium is $\lambda = h/mv'$.Substituting $v' = 0.8v$, we get $\lambda = h/(m \times 0.8v) = (1/0.8) \times (h/mv)$.Since $\lambda_0 = h/mv$, we have $\lambda = (1/0.8) \times \lambda_0 = 1.25 \lambda_0$.Comparing this with $\alpha\lambda_0$, we find that $\alpha = 1.25$.

Class 12 Physics Dual Nature of Radiation and matter Matter Waves and de Broglie Wavelength

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An electron is travelling with a velocity $v$ in free space and when it enters a medium, its velocity is reduced by $20\%$. The de Broglie wavelength of electron in the medium is $\alpha\lambda_0$, where $\lambda_0$ is its de Broglie wavelength in free space. The value of $\alpha$ is . . . . . . .

JEE MAIN 2026 All JEE MAIN

A
$1.2$
B
$1$
C
$1.25$
D
$0.75$

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Class 12

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Dual Nature of Radiation and matter

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Matter Waves and de Broglie Wavelength

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Which one of the following statements is not true about de-Broglie waves?

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An electron beam of energy $10 \, KeV$ is incident on a metallic foil. If the interatomic distance is $0.2454 \, \mathring{A}$,then find the angle of diffraction in degrees. $(\sqrt{150} = 12.27)$

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If $\lambda_0$ is the de-Broglie wavelength for a proton accelerated through a potential difference of $100 \ V$,the de-Broglie wavelength for an $\alpha$-particle accelerated through the same potential difference is

DifficultTS EAMCET 2002

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The idea of matter waves was given by

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An electron of mass $m$ has de-Broglie wavelength $\lambda$ when accelerated through potential difference $V$. When a proton of mass $M$ is accelerated through a potential difference of $9V$,the de-Broglie wavelength associated with it will be (Assume that wavelength is determined at low voltage).

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An electron is travelling with a velocity $v$ in free space and when it enters a medium, its velocity is reduced by $20\%$. The de Broglie wavelength of electron in the medium is $\alpha\lambda_0$, where $\lambda_0$ is its de Broglie wavelength in free space. The value of $\alpha$ is . . . . . . .

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Which one of the following statements is not true about de-Broglie waves?

An electron beam of energy $10 \, KeV$ is incident on a metallic foil. If the interatomic distance is $0.2454 \, \mathring{A}$,then find the angle of diffraction in degrees. $(\sqrt{150} = 12.27)$

If $\lambda_0$ is the de-Broglie wavelength for a proton accelerated through a potential difference of $100 \ V$,the de-Broglie wavelength for an $\alpha$-particle accelerated through the same potential difference is

The idea of matter waves was given by

An electron of mass $m$ has de-Broglie wavelength $\lambda$ when accelerated through potential difference $V$. When a proton of mass $M$ is accelerated through a potential difference of $9V$,the de-Broglie wavelength associated with it will be (Assume that wavelength is determined at low voltage).

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