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(C) The electric current $i$ produced by an electron moving in a circular orbit of radius $r$ with speed $v$ is given by $i = \frac{ev}{2\pi r}$.The m

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$\sqrt{v/B}$

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(C) The electric current $i$ produced by an electron moving in a circular orbit of radius $r$ with speed $v$ is given by $i = \frac{ev}{2\pi r}$.The magnetic field $B$ at the centre of the circular current loop is given by $B = \frac{\mu_0 i}{2r}$.Substituting the value of $i$ into the expression for $B$,we get $B = \frac{\mu_0}{2r} \cdot \frac{ev}{2\pi r} = \frac{\mu_0 ev}{4\pi r^2}$.Rearranging the formula to solve for $r^2$,we get $r^2 = \frac{\mu_0 ev}{4\pi B}$.Taking the square root of both sides,we find $r = \sqrt{\frac{\mu_0 ev}{4\pi B}}$.Since $\mu_0$,$e$,and $4\pi$ are constants,the radius $r$ is proportional to $\sqrt{v/B}$.

An electron moves in a circular orbit with a uniform speed $v$. It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to

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