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(B) For a $bcc$ structure,the number of atoms per unit cell,$z = 2$. Given: Atomic mass $M = 100 \ g/mol$,edge length $a = 400 \ pm = 400 	imes 10^{-

Vedclass · Accepted Answer

$5.188$

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(B) For a $bcc$ structure,the number of atoms per unit cell,$z = 2$. Given: Atomic mass $M = 100 \ g/mol$,edge length $a = 400 \ pm = 400 	imes 10^{-10} \ cm$,and Avogadro's number $N_A = 6.023 	imes 10^{23} \ mol^{-1}$. The formula for density is $ho = \frac{z 	imes M}{N_A 	imes a^3}$. Substituting the values: $ho = \frac{2 	imes 100}{6.023 	imes 10^{23} 	imes (400 	imes 10^{-10})^3}$. $ho = \frac{200}{6.023 	imes 10^{23} 	imes 64 	imes 10^{-24}} = \frac{200}{38.5472} \approx 5.188 \ g/cm^3$.

An element (atomic mass $= 100 \ g/mol$) having $bcc$ structure has a unit cell edge of $400 \ pm$. The density of the element is ................. $g/cm^3$.

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