An element $E$ has an ionisation enthalpy value of $374 \ kJ \ mol^{-1}$. $E$ reacts with elements $A, B, C$ and $D$ with electron gain enthalpy values of $-328, -349, -325$ and $-295 \ kJ \ mol^{-1}$,respectively. The correct order of the products $EA, EB, EC$ and $ED$ in terms of ionic character is $:$

  • A
    $EB > EA > EC > ED$
  • B
    $ED > EC > EA > EB$
  • C
    $EA > EB > EC > ED$
  • D
    $ED > EC > EB > EA$

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Similar Questions

In a period, the first ionisation enthalpy of the element at the extreme left and the negative electron gain enthalpy of the extreme right element, except noble gases, are respectively.

In what properties do the first elements of a group differ from the subsequent elements of the same group?

In which of the following arrangements is the order $NOT$ according to the property indicated against it?

Anything that influences the valence electrons will affect the chemistry of the element. Which one of the following factors does not affect the valence shell?
$(a)$ Valence principal quantum number $(n)$
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$(c)$ Nuclear mass
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Match List-$I$ with List-$II$.
List-$I$ (Elements)List-$II$ (Properties)
$A. Cl, S$$I. \text{Elements with highest electronegativity}$
$B. Ge, As$$II. \text{Elements with largest atomic size}$
$C. Fr, Ra$$III. \text{Elements which show properties of both metals and non-metals}$
$D. F, O$$IV. \text{Elements with highest negative electron gain enthalpy}$

Choose the correct answer from the options given below:

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