An elevator weighing 6000, kg is pulled upwar | vedclass

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(D) The forces acting on the elevator are the tension $T$ in the cable acting upward and the gravitational force $mg$ acting downward.According to New

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$90000$

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(D) The forces acting on the elevator are the tension $T$ in the cable acting upward and the gravitational force $mg$ acting downward.According to Newton's second law of motion,the net force is $F_{net} = T - mg = ma$.Rearranging for tension,we get $T = m(g + a)$.Given values are $m = 6000\, kg$,$g = 10\, m/s^2$,and $a = 5\, m/s^2$.Substituting these values into the equation: $T = 6000 	imes (10 + 5) = 6000 	imes 15 = 90000\, N$.

An elevator weighing $6000\, kg$ is pulled upward by a cable with an acceleration of $5\, m/s^2$. Taking $g$ to be $10\, m/s^2$,then the tension in the cable is ........... $N$.

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