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(A) The energy required to remove the first electron from a neutral helium atom $(He)$ is given as $E_1 = 24.6\ eV$.After removing the first electron,

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$79$

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(A) The energy required to remove the first electron from a neutral helium atom $(He)$ is given as $E_1 = 24.6\ eV$.After removing the first electron,the remaining system is a $He^+$ ion,which is a hydrogen-like atom with atomic number $Z = 2$.The energy required to remove the second electron from the ground state of a hydrogen-like ion is given by the formula $E_n = 13.6 	imes Z^2\,eV$.For $He^+$,$Z = 2$,so the energy required to remove the second electron is $E_2 = 13.6 	imes (2)^2 = 13.6 	imes 4 = 54.4\ eV$.The total energy required to remove both electrons is the sum of the energies required for each step: $E_{total} = E_1 + E_2 = 24.6\ eV + 54.4\ eV = 79\ eV$.

An energy of $24.6\ eV$ is required to remove one of the electrons from a neutral helium atom. The energy (in $eV$) required to remove both the electrons from a neutral helium atom is

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