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(A) The engine is moving a mass up an inclined plane at a constant velocity. The force required to move the mass up the plane must balance the compone

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$5$

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(A) The engine is moving a mass up an inclined plane at a constant velocity. The force required to move the mass up the plane must balance the component of the gravitational force acting down the plane.Force $F = mg \sin 	heta$.Given that the inclination is $1$ in $50$, we have $\sin 	heta = 1/50$.Taking $g = 10 \ ms^{-2}$, the force is $F = 5000 	imes 10 	imes (1/50) = 1000 \ N$.The power $P$ is given by $P = F 	imes v$, where $v = 5 \ ms^{-1}$.$P = 1000 \ N 	imes 5 \ ms^{-1} = 5000 \ W = 5 \ kW$.

An engine is dragging a mass of $5000 \ kg$ with a velocity of $5 \ ms^{-1}$ along a smooth inclined plane of inclination $1$ in $50$. Then the power of the engine is (in $kW$)

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