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(C) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. Here,$P_{ext} = 1 	imes 10^

Vedclass · Accepted Answer

$-900 \ J$

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(C) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. Here,$P_{ext} = 1 	imes 10^5 \ N \ m^{-2}$,$V_1 = 1 	imes 10^{-3} \ m^3$,and $V_2 = 1 	imes 10^{-2} \ m^3$. $\Delta V = V_2 - V_1 = (1 	imes 10^{-2} - 1 	imes 10^{-3}) \ m^3 = (10 	imes 10^{-3} - 1 	imes 10^{-3}) \ m^3 = 9 	imes 10^{-3} \ m^3$. Substituting the values: $W = -(1 	imes 10^5 \ N \ m^{-2}) 	imes (9 	imes 10^{-3} \ m^3) = -900 \ J$. Thus,the work done is $-900 \ J$.

An ideal gas expands in volume from $1 \times 10^{-3} \ m^3$ to $1 \times 10^{-2} \ m^3$ at $300 \ K$ against a constant pressure of $1 \times 10^5 \ N \ m^{-2}$. The work done is

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