An ideal gas is expanded from 1 times 10^{-3} | vedclass

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(D) The work done during expansion against constant external pressure is given by the formula: $W = -P_{ex} \Delta V$. Given: $P_{ex} = 1 	imes 10^5

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$-900 \,J$

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(D) The work done during expansion against constant external pressure is given by the formula: $W = -P_{ex} \Delta V$. Given: $P_{ex} = 1 	imes 10^5 \,N/m^2$ $V_1 = 1 	imes 10^{-3} \,m^3$ $V_2 = 1 	imes 10^{-2} \,m^3 = 10 	imes 10^{-3} \,m^3$ Change in volume: $\Delta V = V_2 - V_1 = (10 	imes 10^{-3} - 1 	imes 10^{-3}) \,m^3 = 9 	imes 10^{-3} \,m^3$ Calculating work: $W = -(1 	imes 10^5 \,N/m^2) 	imes (9 	imes 10^{-3} \,m^3)$ $W = -9 	imes 10^2 \,J = -900 \,J$

An ideal gas is expanded from $1 \times 10^{-3} \,m^3$ to $1 \times 10^{-2} \,m^3$ against a constant external pressure of $1 \times 10^5 \,N/m^2$ at $300 \,K$. The work done is

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