An ideal monoatomic gas expands at constant p | vedclass

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(A) Given: Work done by the gas, $W = 200 \,J$. For an ideal monoatomic gas expanding at constant pressure, the heat absorbed is given by $Q = n C_p \

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(A) Given: Work done by the gas, $W = 200 \,J$. For an ideal monoatomic gas expanding at constant pressure, the heat absorbed is given by $Q = n C_p \Delta T$. The work done is given by $W = n R \Delta T$. Taking the ratio of $Q$ to $W$: $\frac{Q}{W} = \frac{n C_p \Delta T}{n R \Delta T} = \frac{C_p}{R}$. For a monoatomic gas, the molar heat capacity at constant volume is $C_v = \frac{3}{2} R = 1.5 R$. Using the relation $C_p = C_v + R$, we get $C_p = 1.5 R + R = 2.5 R$. Substituting this into the ratio: $\frac{Q}{W} = \frac{2.5 R}{R} = 2.5$. Therefore, $Q = 2.5 	imes W = 2.5 	imes 200 \,J = 500 \,J$.

An ideal monoatomic gas expands at constant pressure. The work done by the gas on its environment is $200 \,J$, then the heat absorbed by the gas during the process is (in $\,J$)

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