An incompressible fluid (ideal fluid) is flow | vedclass

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(D) According to the equation of continuity for an incompressible fluid, the product of the cross-sectional area and the velocity of the fluid remains

Vedclass · Accepted Answer

$K_P > K_Q$

Vedclass · Answer

(D) According to the equation of continuity for an incompressible fluid, the product of the cross-sectional area and the velocity of the fluid remains constant, i.e.,$A_P v_P = A_Q v_Q$.From the figure, it is clear that the cross-sectional area at $P$ is smaller than at $Q$ $(A_P Therefore, the velocity of the fluid at $P$ must be greater than at $Q$ $(v_P > v_Q)$.The kinetic energy per unit volume of a fluid is given by the formula $K = \frac{1}{2} \rho v^2$, where $\rho$ is the density of the fluid and $v$ is its velocity.Since $v_P > v_Q$, it follows that $\frac{1}{2} \rho v_P^2 > \frac{1}{2} \rho v_Q^2$.Thus, $K_P > K_Q$.

An incompressible fluid (ideal fluid) is flowing through a non-uniform cross-sectional tube $PQ$ from end $P$ to end $Q$. If $K_P$ and $K_Q$ are the kinetic energy per unit volume of the fluid at end $P$ and end $Q$ respectively, then

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