An inductance coil has a reactance of 100, Om | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The impedance $Z$ of an $RL$ circuit is given by $Z = \sqrt{R^2 + X_L^2} = 100\, \Omega$. Given that the voltage leads the current by $\phi = 45^{

Vedclass · Accepted Answer

$1.1 	imes 10^{-2}\; H$

Vedclass · Answer

(A) The impedance $Z$ of an $RL$ circuit is given by $Z = \sqrt{R^2 + X_L^2} = 100\, \Omega$. Given that the voltage leads the current by $\phi = 45^{\circ}$,we have $	an \phi = \frac{X_L}{R}$. Since $	an 45^{\circ} = 1$,it follows that $X_L = R$. Substituting $X_L = R$ into the impedance equation: $\sqrt{X_L^2 + X_L^2} = 100 \Rightarrow \sqrt{2} X_L = 100$. Thus,$X_L = \frac{100}{\sqrt{2}} = 50\sqrt{2}\, \Omega$. Since $X_L = 2\pi f L$,we have $L = \frac{X_L}{2\pi f} = \frac{50\sqrt{2}}{2 	imes \pi 	imes 1000}$. $L = \frac{25\sqrt{2}}{1000\pi} \approx \frac{25 	imes 1.414}{3141.59} \approx 0.01125\, H = 1.125 	imes 10^{-2}\, H$.

An inductance coil has a reactance of $100\, \Omega$. When an $AC$ signal of frequency $1000\, Hz$ is applied to the coil,the applied voltage leads the current by $45^{\circ}$. The self-inductance of the coil is

Similar Questions

In an $LR$-circuit,the inductive reactance is equal to the resistance $R$ of the circuit. An e.m.f. $E = E_0 \cos(\omega t)$ is applied to the circuit. The power consumed in the circuit is:

An $AC$ circuit has an inductor and a resistor of resistance $R$ in series,such that $X_L = 3R$. Now,a capacitor is added in series such that $X_C = 2R$. The ratio of the new power factor to the old power factor of the circuit is $\sqrt{5} : x$. The value of $x$ is ...... .

In an $L-C-R$ series circuit,if $V$,$V_R$,$V_L$,and $V_C$ are the voltages across the source,resistor,inductor,and capacitor respectively at any instant,choose the correct relation.

In an $RC$ $AC$ circuit,the maximum voltage and maximum current are $100 \ V$ and $1.1 \ A$ respectively. If $X_{C} = 60 \ \Omega$ and $R = 80 \ \Omega$,then the power consumed in the circuit will be . . . . . . . (in $W$)

An electric bulb and a capacitor are connected in series with an $AC$ source. On increasing the frequency of the source,the brightness of the bulb

Vedclass Test Series

Exam Paper Generator

Online Exam Module