An inductance of $0.2 \ H$ and resistance of $100 \ \Omega$ are connected in series to an $AC$ of $180 \ V$,$50 \ Hz$ supply. The $RMS$ current flowing in the circuit will be . . . . . . (Take $\pi^2$ as $10$). (in $A$)

The power factor of an $R-L$ circuit is $\frac{1}{\sqrt{2}}$. If the frequency of $AC$ is doubled,the power factor will now be

When $100\, V$ $DC$ is applied across a solenoid,a current of $1\, A$ flows in it. When $100\, V$ $AC$ is applied across the same coil,the current drops to $0.5\, A$. If the frequency of the $AC$ source is $50\, Hz$,the impedance and inductance of the solenoid are:

$A$ series $LCR$ circuit containing an $a.c.$ source of $100 \text{ V}$ has an inductor and a capacitor of reactance $24 \text{ } \Omega$ and $16 \text{ } \Omega$ respectively. If a resistance of $6 \text{ } \Omega$ is connected in series, then the potential difference across the series combination of inductor and capacitor only is: (in $\text{ V}$)

When $100 \, V$ $DC$ is supplied across a solenoid,a current of $1.0 \, A$ flows in it. When $100 \, V$ $AC$ is applied across the same coil,the current drops to $0.5 \, A$. If the frequency of the $AC$ source is $50 \, Hz$,then the impedance and inductance of the solenoid are:

If in an $AC$,$LC$ series circuit $X_{C} > X_{L}$,then the potential . . . . . . .