An inductance of 1, mH,a capacitor of 10, mu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that the inductive reactance $X_L$ is equal to the capacitive reactance $X_C$,so $X_L = X_C = X$.We know that $X_L = \omega L$ and $X_C = \f

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(D) Given that the inductive reactance $X_L$ is equal to the capacitive reactance $X_C$,so $X_L = X_C = X$.We know that $X_L = \omega L$ and $X_C = \frac{1}{\omega C}$.Since $X_L = X_C$,we have $\omega L = \frac{1}{\omega C}$,which implies $\omega^2 = \frac{1}{LC}$.Substituting the given values: $L = 1\, mH = 10^{-3}\, H$ and $C = 10\, \mu F = 10 	imes 10^{-6}\, F = 10^{-5}\, F$.$\omega^2 = \frac{1}{10^{-3} 	imes 10^{-5}} = \frac{1}{10^{-8}} = 10^8$.Therefore,$\omega = \sqrt{10^8} = 10^4\, rad/s$.The reactance $X$ is given by $X = \omega L = 10^4 	imes 10^{-3} = 10\, \Omega$.

An inductance of $1\, mH$,a capacitor of $10\, \mu F$,and a resistance of $50\, \Omega$ are connected in series. The reactances of the inductor and the capacitor are the same. The reactance of either of them will be........$\Omega$.

Similar Questions

$A$ circuit containing resistance $R_1$,inductance $L_1$,and capacitance $C_1$ connected in series resonates at the same frequency $f_r$ as another circuit containing $R_2$,$L_2$,and $C_2$ in series. If the two circuits are connected in series,then the new frequency at resonance is

In the circuit shown,the $AC$ source has voltage $V=20 \cos (\omega t) \text{ V}$ with $\omega=2000 \text{ rad/s}$. The magnitude of the amplitude current will be nearly

$A$ $L-C-R$ series $AC$ circuit is tuned to resonance. The impedance of the circuit is now . . . . . . .

An $LCR$ circuit as shown in the figure is connected to a voltage source $V_{ac}$ whose frequency can be varied. The frequency,at which the voltage across the resistor is maximum,is......$Hz$.

$A$ series $LCR$ circuit containing a resistance of $120\,\Omega$ has a resonance frequency of $4 \times 10^5\, rad\, s^{-1}$. The voltages,at resonance,across the resistance and inductance are $60\,V$ and $40\,V$ respectively. The values of $L$ and $C$ respectively are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module