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(B) Given: Resistance $R = 10 \, \Omega$,Inductance $L = 2.0 \, H$,Voltage $V = 120 \, V$,Frequency $f = 60 \, Hz$.First,calculate the inductive react

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$0.16$

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(B) Given: Resistance $R = 10 \, \Omega$,Inductance $L = 2.0 \, H$,Voltage $V = 120 \, V$,Frequency $f = 60 \, Hz$.First,calculate the inductive reactance $X_L = 2\pi f L$.$X_L = 2 	imes 3.14159 	imes 60 	imes 2.0 \approx 753.98 \, \Omega$.The impedance of the $RL$ circuit is $Z = \sqrt{R^2 + X_L^2}$.$Z = \sqrt{10^2 + 753.98^2} = \sqrt{100 + 568485.8} \approx \sqrt{568585.8} \approx 754.05 \, \Omega$.The current $I$ in the circuit is given by $I = \frac{V}{Z}$.$I = \frac{120}{754.05} \approx 0.159 \, A$.Rounding to two decimal places,the current is approximately $0.16 \, A$.

An inductive circuit contains a resistance of $10 \, \Omega$ and an inductance of $2.0 \, H$. If an $AC$ voltage of $120 \, V$ and frequency of $60 \, Hz$ is applied to this circuit,the current in the circuit would be nearly......$A$.

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