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Question

(B) The impedance $Z$ of an $RL$ series circuit is given by $Z = \sqrt{R^2 + X_L^2}$.Here,$R = 10\,\Omega$,$L = 2.0\,H$,$V = 120\,V$,and $f = 60\,Hz$.

Vedclass · Accepted Answer

$0.16$

Vedclass · Answer

(B) The impedance $Z$ of an $RL$ series circuit is given by $Z = \sqrt{R^2 + X_L^2}$.Here,$R = 10\,\Omega$,$L = 2.0\,H$,$V = 120\,V$,and $f = 60\,Hz$.The inductive reactance is $X_L = 2\pi f L = 2 	imes 3.1416 	imes 60 	imes 2.0 \approx 753.98\,\Omega$.Now,calculate the impedance: $Z = \sqrt{10^2 + 753.98^2} \approx \sqrt{100 + 568485.8} \approx \sqrt{568585.8} \approx 754.05\,\Omega$.The current $I$ is given by $I = \frac{V}{Z} = \frac{120}{754.05} \approx 0.159\,A$.Rounding to two decimal places,the current is nearly $0.16\,A$.

An inductive circuit contains a resistance of $10\,\Omega$ and an inductance of $2.0\,H$. If an $AC$ voltage of $120\,V$ and frequency $60\,Hz$ is applied to this circuit,the current would be nearly ................$A$.

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