An inductive circuit contains a resistance of $10 \, \Omega$ and an inductance of $20 \, H$. If an $AC$ voltage of $120 \, V$ and frequency $60 \, Hz$ is applied to this circuit, the current would be nearly: (in $A$)

$A$ pure inductor of $25.48 \ mH$ and a pure resistor of $8 \ \Omega$ are connected in series with an $AC$ source of frequency $50 \ Hz$. The phase difference between current $(I)$ and voltage $(V)$ in this circuit is . . . . . . . (in $^{\circ}$)

An ideal choke draws a current of $8 \, A$ when connected to an $AC$ supply of $100 \, V, 50 \, Hz$. $A$ pure resistor draws a current of $10 \, A$ when connected to the same source. The ideal choke and the resistor are connected in series and then connected to the $AC$ source of $150 \, V, 40 \, Hz$. The current in the circuit becomes

In the given circuit,the potential difference across the resistance is $54 \, V$ and the power consumed by it is $16 \, W$. If the $AC$ frequency is $60 \, Hz$,find the value of $L$ in $H$.

$A$ resistance of $300\,\Omega$ and an inductance of $\frac{1}{\pi}\,H$ are connected in series to an $AC$ voltage source of $20\,V$ and $200\,Hz$ frequency. The phase angle between the voltage and current is:

In the circuit shown,if the $emf$ of the source at an instant is $5 \, V$,and the potential difference across the capacitor at the same instant is $4 \, V$,then the potential difference across $R$ at that instant may be ..... $V$.