An ionic compound is expected to have a tetra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The structure of an ionic compound is determined by the radius ratio of the cation to the anion $(r_{+} / r_{-})$. Based on the standard radius ra

Vedclass · Accepted Answer

$0.225$ to $0.414$

Vedclass · Answer

(B) The structure of an ionic compound is determined by the radius ratio of the cation to the anion $(r_{+} / r_{-})$. Based on the standard radius ratio rules for coordination geometry:- For $r_{+} / r_{-} - For $0.155 - 0.225$,the structure is planar triangular.- For $0.225 - 0.414$,the structure is tetrahedral.- For $0.414 - 0.732$,the structure is octahedral.- For $0.732 - 1$,the structure is body-centered cubic $(bcc)$.Therefore,the tetrahedral structure corresponds to the range $0.225$ to $0.414$.

An ionic compound is expected to have a tetrahedral structure if the radius ratio $r_{+} / r_{-}$ lies in the range of:

Similar Questions

In the fluorite structure,the coordination number of the $Ca^{2+}$ ion is.....

The number of close neighbours in a body-centred cubic $(BCC)$ lattice of identical spheres is:

The structure of $MgO$ is similar to $NaCl$. What would be the coordination number of magnesium?

The structure of $MgO$ is similar to that of $NaCl$. What is the coordination number of $Mg^{2+}$?

Total volume of atoms present in a face-centred cubic unit cell of a metal is ($r$ is atomic radius)

Vedclass Test Series

Exam Paper Generator

Online Exam Module