An isotope of a 'parent' nucleus is produced | vedclass

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(C) An isotope has the same atomic number $(Z)$ but a different mass number $(A)$.When a nucleus loses one $\alpha$-particle $(_{2}He^{4})$,the atomic

Vedclass · Accepted Answer

One $\alpha$ and two $\beta$-particles

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(C) An isotope has the same atomic number $(Z)$ but a different mass number $(A)$.When a nucleus loses one $\alpha$-particle $(_{2}He^{4})$,the atomic number decreases by $2$ and the mass number decreases by $4$.When a nucleus loses one $\beta$-particle $(_{-1}e^{0})$,the atomic number increases by $1$ and the mass number remains unchanged.To maintain the same atomic number $Z$,the net change in $Z$ must be zero.Loss of one $\alpha$-particle $(Z-2)$ followed by two $\beta$-particles $(Z-2+1+1 = Z)$ results in the same atomic number.The mass number changes by $-4$ (from the $\alpha$-particle),thus producing an isotope.Therefore,the correct option is $(C)$.

An isotope of a 'parent' nucleus is produced when it loses:

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