An object O is placed at 7 ,cm to the left of | vedclass

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(C) Given, distance between object and mirror, $u = -7 \,cm$.Radius of curvature, $R = -12 \,cm$.Therefore, focal length, $f = \frac{R}{2} = \frac{-12

Vedclass · Accepted Answer

$42 \,cm$ from the mirror to the left.

Vedclass · Answer

(C) Given, distance between object and mirror, $u = -7 \,cm$.Radius of curvature, $R = -12 \,cm$.Therefore, focal length, $f = \frac{R}{2} = \frac{-12}{2} = -6 \,cm$.Using the mirror formula, $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Substituting the given values:$\frac{1}{v} + \frac{1}{-7} = \frac{1}{-6}$$\frac{1}{v} = \frac{1}{7} - \frac{1}{6} = \frac{6 - 7}{42} = -\frac{1}{42}$$v = -42 \,cm$.The negative sign indicates that the image is formed at a distance of $42 \,cm$ to the left of the mirror.

An object $O$ is placed at $7 \,cm$ to the left of a concave mirror of radius of curvature $12 \,cm$ as shown in the figure. The position of the image will be at a distance of

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