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(D) The hydraulic stress is equal to the hydrostatic pressure $P$ at depth $h$,given by $P = h \rho g$.Here,$h = 2 \, km = 2000 \, m$,$\rho = 1000 \,

Vedclass · Accepted Answer

$1.44 	imes 10^{9} \, N \, m^{-2}$

Vedclass · Answer

(D) The hydraulic stress is equal to the hydrostatic pressure $P$ at depth $h$,given by $P = h ho g$.Here,$h = 2 \, km = 2000 \, m$,$ho = 1000 \, kg \, m^{-3}$,and $g = 9.8 \, m \, s^{-2}$.$P = 2000 	imes 1000 	imes 9.8 = 1.96 	imes 10^{7} \, N \, m^{-2}$.The hydraulic strain is the fractional compression $\frac{\Delta V}{V} = 1.36 \, \% = 1.36 	imes 10^{-2}$.The ratio of hydraulic stress to hydraulic strain is the Bulk Modulus $B = \frac{P}{\Delta V / V}$.$B = \frac{1.96 	imes 10^{7}}{1.36 	imes 10^{-2}} \approx 1.44 	imes 10^{9} \, N \, m^{-2}$.

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