An object is placed at 20 , cm from a convex | vedclass

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(C) Given: Object distance $u = -20 \, cm$,Focal length $f = +10 \, cm$ (for a convex mirror).Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \

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Virtual and at $\frac{20}{3} \, cm$ from the mirror

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(C) Given: Object distance $u = -20 \, cm$,Focal length $f = +10 \, cm$ (for a convex mirror).Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the values: $\frac{1}{10} = \frac{1}{v} + \frac{1}{-20}$.Rearranging for $v$: $\frac{1}{v} = \frac{1}{10} + \frac{1}{20} = \frac{2+1}{20} = \frac{3}{20}$.Thus,$v = +\frac{20}{3} \, cm$.Since $v$ is positive,the image is virtual and formed behind the mirror at a distance of $\frac{20}{3} \, cm$.

An object is placed at $20 \, cm$ from a convex mirror of focal length $10 \, cm$. The image formed by the mirror is

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