An object is placed at a distance of 12 ,{cm} | vedclass

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(C) For the image of the object to coincide with the object,the light rays must strike the convex mirror normally. This happens if the light rays are

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$50$

Vedclass · Answer

(C) For the image of the object to coincide with the object,the light rays must strike the convex mirror normally. This happens if the light rays are directed towards the center of curvature $(C)$ of the convex mirror.Given the focal length of the convex mirror $f = 15 \,{cm}$,the radius of curvature is $R = 2f = 30 \,{cm}$.Thus,the light rays from the lens must converge at a point $30 \,{cm}$ behind the mirror.When the mirror is removed,the lens forms a real and inverted image at the same point where the rays were converging,which is $30 \,{cm}$ behind the mirror.The total distance of this image from the object is the sum of the distance of the object from the lens $(12 \,{cm})$,the distance of the lens from the mirror $(8 \,{cm})$,and the distance of the image from the mirror $(30 \,{cm})$.Total distance = $12 \,{cm} + 8 \,{cm} + 30 \,{cm} = 50 \,{cm}$.

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