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(D) Given: Focal length $f = -10 	ext{ cm}$ (for a concave mirror),Object distance $u = -20 	ext{ cm}$.Using the mirror formula: $\frac{1}{f} = \fra

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At the center of curvature

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(D) Given: Focal length $f = -10 	ext{ cm}$ (for a concave mirror),Object distance $u = -20 	ext{ cm}$.Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the values: $\frac{1}{-10} = \frac{1}{v} + \frac{1}{-20}$.Rearranging: $\frac{1}{v} = \frac{1}{20} - \frac{1}{10} = \frac{1 - 2}{20} = -\frac{1}{20}$.Therefore,$v = -20 	ext{ cm}$.Since the object is placed at $2f$ $(2 	imes 10 	ext{ cm} = 20 	ext{ cm})$,the image is also formed at $2f$,which is the center of curvature.

An object is placed at a distance of $20 \text{ cm}$ in front of a concave mirror of focal length $10 \text{ cm}$. Where will the image be formed?

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