An object is placed at a distance of 18 cm i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Object distance $u = -18 \ cm$ (in front of the mirror).Image distance $v = +4 \ cm$ (on the other side of the mirror).Using the mirror for

Vedclass · Accepted Answer

$5.14 \ cm$,convex mirror and virtual image

Vedclass · Answer

(C) Given: Object distance $u = -18 \ cm$ (in front of the mirror).Image distance $v = +4 \ cm$ (on the other side of the mirror).Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{4} + \frac{1}{-18} = \frac{9 - 2}{36} = \frac{7}{36}$.Therefore,$f = \frac{36}{7} \ cm \approx 5.14 \ cm$.Since the focal length $f$ is positive,the mirror is a convex mirror.Since the image is formed on the other side of the mirror,it is a virtual image.

An object is placed at a distance of $18 \ cm$ in front of a mirror. If the image is formed at a distance of $4 \ cm$ on the other side,then the focal length,nature of the mirror,and nature of the image are respectively:

Similar Questions

An object is placed at a distance of $10 \, cm$ from a concave mirror of focal length $20 \, cm$. The image formed will be .......

The image formed by a convex mirror of focal length $30 \,cm$ is a quarter of the size of the object. The distance of the object from the mirror is (in $\,cm$)

An object is placed in front of a concave mirror of focal length $15 \ cm$. The image formed is twice the size of the object. If the image is virtual,the position of the object is at ...... $cm$.

In the case of a spherical mirror,if the object distance $(u)$ and image distance $(v)$ are measured from the pole,then the graph plotted between $(1/u)$ and $(1/v)$ will be:

If the coordinates of the position of an object are $(-60 \, cm, 6 \, cm)$,then the coordinates of the image will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module