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(B) The object moves in a circular path with radius $r = 2\,m$ and constant speed $v = 4\,m/s$.The magnitude of centripetal acceleration is $a_c = \fr

Vedclass · Accepted Answer

$v = 4 \hat{j}\,m/s, a = 8 \hat{i}\,m/s^2$

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(B) The object moves in a circular path with radius $r = 2\,m$ and constant speed $v = 4\,m/s$.The magnitude of centripetal acceleration is $a_c = \frac{v^2}{r} = \frac{4^2}{2} = \frac{16}{2} = 8\,m/s^2$.At $x = +2\,m$,the velocity is $-4 \hat{j}\,m/s$,which implies the object is moving in the clockwise direction.At $x = -2\,m$,the object will be at the diametrically opposite point.Since it is moving clockwise,at $x = -2\,m$,the velocity vector will be directed upwards,so $v = 4 \hat{j}\,m/s$.The centripetal acceleration is always directed towards the centre $(0,0)$. At $x = -2\,m$,the centre is to the right,so the acceleration is directed along the positive $x$-axis,$a = 8 \hat{i}\,m/s^2$.

An object moves at a constant speed along a circular path in a horizontal plane with its centre at the origin. When the object is at $x = +2\,m$,its velocity is $-4 \hat{j}\,m/s$. The object's velocity $(v)$ and acceleration $(a)$ at $x = -2\,m$ will be

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